Given: ∆ABC Prove: The three medians of ∆ABC intersect at a common point. When written in the correct order, the two-column proof below describes the statements and justifications for proving the three medians of a triangle all intersect in one point. Statements Justifications Point F is a midpoint of Line segment AB Point E is a midpoint of Line segment AC Draw Line segment BE Draw Line segment FC by Construction Point G is the point of intersection between Line segment BE and Line segment FC Intersecting Lines Postulate Draw Line segment AG by Const
Point D is the point of intersection between Line segment AG and Line segment BC Intersecting Lines Postulate Point H lies on Line segment AG such that Line segment AG ≅ Line segment GH by Construction I BGCH is a parallelogram Properties of a Parallelogram (opposite sides are parallel) II Line segment BD ≅ Line segment DC Properties of a Parallelogram (diagonals bisect each other) III Line segment GC is parallel to line segment BH and Line segment BG is parallel to line segment HC Substitution IV Line segment FG is parallel to line segment BH and Line segment GE is parallel to line segment HC Midsegment Theorem Line segment AD is a median Definition of a Median
Which is the most logical order of statements and justifications I, II, III, and IV to complete the proof?
Which is the most logical order of statements and justifications I, II, III, and IV to complete the proof? III, IV, II, I IV, III, I, II III, IV, I, II IV, III, II, I
this is the last nasty sucker for this worksheet :)
hey gane
any tips?
this is tough reading.
ahh
let me make it simpler
give me 5 minutes
k
Statements: Point F is at midpoint of line segment AB. Point E is a midpoint of line segment AC. Draw line segment BE. Draw line segment FC.
Justifications: By construction.
Statements: Point G is the point of intersection between line segment BE and line segment FC.
Reasons: Intersecting Lines Postulate
Statements: Draw line segment AG.
Justifications: Intersecting Lines Postulate
Statements: Point D is the point of intersection between like segment AG and line segment BC.
opps
The Justification for the drawing of line segment AG was by construction
The Point D intersection one is Intersecting Lines Postulate
OK, I have a handle on this. But you are the one who is supposed to learn how to do it.
Point H lies on line segment AG such that line segment AG is congruent to line segment GH.
can you teach me?
Justification: By construction
I. BGCH is a parallelogram.
Justification: Properties of a Parallelogram(opposite sides are parallel)
II line segment BD is congruent to line segment DC
First, read I. it can't be first, because we haven't said anything about parallel lines. read II should it come before or after I ?
Justification: Properties of Parallelograms (diagonals bisect each other)
The one I just wrote was II.
Yes. now read I and II. which ones goes ahead of the other?
Lol, II goes before one
cause like you said, we haven't talked about parallel lines yet
II uses "properties of parallelograms" that means you have to prove you have a parallelogram before you can use II I goes ahead of II
III. Line segment GC is parallel to line segment BH Line segment BG is parallel to line segment HC.
yep
Justification: Substitution
IV. line segment FG is parallel to line segment BH. Line segment GE is parallel to line segment HC
Justification is the Midsegment Theory
III does prove parallel lines. So it comes before I
Line segment AD is a median
Because of Definition of a median
k
makes sense
you can stop typing the question.
So I is last obviously
what is the answer?
Because all of the other reasons have to support that the figure is a parallelogram
So we have narrowed it down to two options
IV, III, II, I or III, IV, II, I
no. but we can work backwards.
I has to be last
right?
In order to prove that the figure is a parallelogram
Because we do not whether its a parallelogram or not until we have used reasons two, three, and four.
I kinda think III goes first
and IV goes second
no. we are trying to prove the 3 medians intersect. the first 2 are easy. the 3rd median goes from A to D. what statement claims: BD=DC (making D the midpoint).?
II. obviously
But it does not go first, either
It could only go last
ohhh
II is the last thing you do before saying AD is a median. So it goes last.
so II. is last
i see
It makes sense now
now what does II use for its justification?
And then 1. goes before II.
I.
I proves a parallelgram and II uses it. so we have ?,?,I, II what is the justification for I?
hmm
I'm going with III.
Cause it proves about the parallel lines
so it has to go before I.
the justification for I is Properties of a Parallelogram (opposite sides are parallel) which statement concludes you have parallel lines?
III.
Like I said
It proves that the lines are parallel
so IV. would have to go at the beginning
and IV must go first.
yep
So it goes IV,III,I,II..?
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