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Mathematics 7 Online
OpenStudy (anonymous):

Given: ∆ABC Prove: The three medians of ∆ABC intersect at a common point. When written in the correct order, the two-column proof below describes the statements and justifications for proving the three medians of a triangle all intersect in one point. Statements Justifications Point F is a midpoint of Line segment AB Point E is a midpoint of Line segment AC Draw Line segment BE Draw Line segment FC by Construction Point G is the point of intersection between Line segment BE and Line segment FC Intersecting Lines Postulate Draw Line segment AG by Const

OpenStudy (anonymous):

Point D is the point of intersection between Line segment AG and Line segment BC Intersecting Lines Postulate Point H lies on Line segment AG such that Line segment AG ≅ Line segment GH by Construction I BGCH is a parallelogram Properties of a Parallelogram (opposite sides are parallel) II Line segment BD ≅ Line segment DC Properties of a Parallelogram (diagonals bisect each other) III Line segment GC is parallel to line segment BH and Line segment BG is parallel to line segment HC Substitution IV Line segment FG is parallel to line segment BH and Line segment GE is parallel to line segment HC Midsegment Theorem Line segment AD is a median Definition of a Median

OpenStudy (anonymous):

Which is the most logical order of statements and justifications I, II, III, and IV to complete the proof?

OpenStudy (anonymous):

Which is the most logical order of statements and justifications I, II, III, and IV to complete the proof? III, IV, II, I IV, III, I, II III, IV, I, II IV, III, II, I

OpenStudy (anonymous):

this is the last nasty sucker for this worksheet :)

OpenStudy (anonymous):

hey gane

OpenStudy (anonymous):

any tips?

OpenStudy (phi):

this is tough reading.

OpenStudy (anonymous):

ahh

OpenStudy (anonymous):

let me make it simpler

OpenStudy (anonymous):

give me 5 minutes

OpenStudy (anonymous):

k

OpenStudy (anonymous):

Statements: Point F is at midpoint of line segment AB. Point E is a midpoint of line segment AC. Draw line segment BE. Draw line segment FC.

OpenStudy (anonymous):

Justifications: By construction.

OpenStudy (anonymous):

Statements: Point G is the point of intersection between line segment BE and line segment FC.

OpenStudy (anonymous):

Reasons: Intersecting Lines Postulate

OpenStudy (anonymous):

Statements: Draw line segment AG.

OpenStudy (anonymous):

Justifications: Intersecting Lines Postulate

OpenStudy (anonymous):

Statements: Point D is the point of intersection between like segment AG and line segment BC.

OpenStudy (anonymous):

opps

OpenStudy (anonymous):

The Justification for the drawing of line segment AG was by construction

OpenStudy (anonymous):

The Point D intersection one is Intersecting Lines Postulate

OpenStudy (phi):

OK, I have a handle on this. But you are the one who is supposed to learn how to do it.

OpenStudy (anonymous):

Point H lies on line segment AG such that line segment AG is congruent to line segment GH.

OpenStudy (anonymous):

can you teach me?

OpenStudy (anonymous):

Justification: By construction

OpenStudy (anonymous):

I. BGCH is a parallelogram.

OpenStudy (anonymous):

Justification: Properties of a Parallelogram(opposite sides are parallel)

OpenStudy (anonymous):

II line segment BD is congruent to line segment DC

OpenStudy (phi):

First, read I. it can't be first, because we haven't said anything about parallel lines. read II should it come before or after I ?

OpenStudy (anonymous):

Justification: Properties of Parallelograms (diagonals bisect each other)

OpenStudy (anonymous):

The one I just wrote was II.

OpenStudy (phi):

Yes. now read I and II. which ones goes ahead of the other?

OpenStudy (anonymous):

Lol, II goes before one

OpenStudy (anonymous):

cause like you said, we haven't talked about parallel lines yet

OpenStudy (phi):

II uses "properties of parallelograms" that means you have to prove you have a parallelogram before you can use II I goes ahead of II

OpenStudy (anonymous):

III. Line segment GC is parallel to line segment BH Line segment BG is parallel to line segment HC.

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

Justification: Substitution

OpenStudy (anonymous):

IV. line segment FG is parallel to line segment BH. Line segment GE is parallel to line segment HC

OpenStudy (anonymous):

Justification is the Midsegment Theory

OpenStudy (phi):

III does prove parallel lines. So it comes before I

OpenStudy (anonymous):

Line segment AD is a median

OpenStudy (anonymous):

Because of Definition of a median

OpenStudy (anonymous):

k

OpenStudy (anonymous):

makes sense

OpenStudy (phi):

you can stop typing the question.

OpenStudy (anonymous):

So I is last obviously

OpenStudy (phi):

what is the answer?

OpenStudy (anonymous):

Because all of the other reasons have to support that the figure is a parallelogram

OpenStudy (anonymous):

So we have narrowed it down to two options

OpenStudy (anonymous):

IV, III, II, I or III, IV, II, I

OpenStudy (phi):

no. but we can work backwards.

OpenStudy (anonymous):

I has to be last

OpenStudy (anonymous):

right?

OpenStudy (anonymous):

In order to prove that the figure is a parallelogram

OpenStudy (anonymous):

Because we do not whether its a parallelogram or not until we have used reasons two, three, and four.

OpenStudy (anonymous):

I kinda think III goes first

OpenStudy (anonymous):

and IV goes second

OpenStudy (phi):

no. we are trying to prove the 3 medians intersect. the first 2 are easy. the 3rd median goes from A to D. what statement claims: BD=DC (making D the midpoint).?

OpenStudy (anonymous):

II. obviously

OpenStudy (anonymous):

But it does not go first, either

OpenStudy (anonymous):

It could only go last

OpenStudy (anonymous):

ohhh

OpenStudy (phi):

II is the last thing you do before saying AD is a median. So it goes last.

OpenStudy (anonymous):

so II. is last

OpenStudy (anonymous):

i see

OpenStudy (anonymous):

It makes sense now

OpenStudy (phi):

now what does II use for its justification?

OpenStudy (anonymous):

And then 1. goes before II.

OpenStudy (anonymous):

I.

OpenStudy (phi):

I proves a parallelgram and II uses it. so we have ?,?,I, II what is the justification for I?

OpenStudy (anonymous):

hmm

OpenStudy (anonymous):

I'm going with III.

OpenStudy (anonymous):

Cause it proves about the parallel lines

OpenStudy (anonymous):

so it has to go before I.

OpenStudy (phi):

the justification for I is Properties of a Parallelogram (opposite sides are parallel) which statement concludes you have parallel lines?

OpenStudy (anonymous):

III.

OpenStudy (anonymous):

Like I said

OpenStudy (anonymous):

It proves that the lines are parallel

OpenStudy (anonymous):

so IV. would have to go at the beginning

OpenStudy (phi):

and IV must go first.

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

So it goes IV,III,I,II..?

OpenStudy (anonymous):

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