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Mathematics 12 Online
OpenStudy (konradzuse):

Find the exponential function y = Cekt that passes through the two given points.(see attached)

OpenStudy (konradzuse):

OpenStudy (konradzuse):

y = Ce^kt y = 5/6 e^ 6k 10 = 5/6 e^6k ln 10 = 30/6k ln 10 = 5k ln(10)/5 = k y = 5/6e ^(ln(10)/5) t y = 5/6e ^4605t

OpenStudy (konradzuse):

Apparently this isn't right... :(

OpenStudy (paxpolaris):

to find the equation you need to solve for C & k plug in x=0, y=5/6 & x=6, y=10 to solve:

OpenStudy (konradzuse):

which I did. Was I correct?

OpenStudy (anonymous):

You plugged them into the wrong place. The 2 equations should be 5/6 = Ce^0 10 = Ce^(6t)

OpenStudy (paxpolaris):

ok i follow you now \[\LARGE 10 = \frac56 e^{6k}\] correct so far...

OpenStudy (anonymous):

yes

OpenStudy (paxpolaris):

\[\Large \implies {10\cdot 6 \over 5}=e^{6k}\]

OpenStudy (konradzuse):

ah that's where I messed up.

OpenStudy (konradzuse):

ln(60)/5 = 6k

OpenStudy (konradzuse):

ln(60)/30 = k

OpenStudy (paxpolaris):

or if you wanted to take ln before this step it should have been \[\Large \ln(10)=\ln \left( \frac56 \right)+6k\]

OpenStudy (konradzuse):

I think we will stick with the other way :).

OpenStudy (paxpolaris):

no... ln(60/5)=6k or \[\Large \ln(12)=6k\]

OpenStudy (konradzuse):

ah :) ln(12)/6? = k

OpenStudy (paxpolaris):

yes

OpenStudy (konradzuse):

alrighty I think I got this now thanks !!! :).

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