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OpenStudy (konradzuse):
Find the exponential function y = Cekt that passes through the two given points.(see attached)
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OpenStudy (konradzuse):
OpenStudy (konradzuse):
y = Ce^kt
y = 5/6 e^ 6k
10 = 5/6 e^6k
ln 10 = 30/6k
ln 10 = 5k
ln(10)/5 = k
y = 5/6e ^(ln(10)/5) t
y = 5/6e ^4605t
OpenStudy (konradzuse):
Apparently this isn't right... :(
OpenStudy (paxpolaris):
to find the equation you need to solve for C & k
plug in x=0, y=5/6
& x=6, y=10
to solve:
OpenStudy (konradzuse):
which I did. Was I correct?
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OpenStudy (anonymous):
You plugged them into the wrong place.
The 2 equations should be
5/6 = Ce^0
10 = Ce^(6t)
OpenStudy (paxpolaris):
ok i follow you now
\[\LARGE 10 = \frac56 e^{6k}\]
correct so far...
OpenStudy (anonymous):
yes
OpenStudy (paxpolaris):
\[\Large \implies {10\cdot 6 \over 5}=e^{6k}\]
OpenStudy (konradzuse):
ah that's where I messed up.
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OpenStudy (konradzuse):
ln(60)/5 = 6k
OpenStudy (konradzuse):
ln(60)/30 = k
OpenStudy (paxpolaris):
or if you wanted to take ln before this step it should have been
\[\Large \ln(10)=\ln \left( \frac56 \right)+6k\]
OpenStudy (konradzuse):
I think we will stick with the other way :).
OpenStudy (paxpolaris):
no...
ln(60/5)=6k
or
\[\Large \ln(12)=6k\]
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OpenStudy (konradzuse):
ah :) ln(12)/6? = k
OpenStudy (paxpolaris):
yes
OpenStudy (konradzuse):
alrighty I think I got this now thanks !!! :).
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