If the product of two consecutive odd integers is decreased by one third the lesser integer, the result is 250. Find the integers.

Question

agent47 · Answer

x*(x+2)-(x/3)=50

mathslover · Answer

let the first integer be x-1 then x+1and then they are decreased by (x-1)/3

therefore 
(x-1)(x+1)-(x-1)/3=250
x^2-1-(x-1)/3=250
(3x^2-3-x+1)=750
3x^2-x-2=750 can u solve it now

anonymous · Answer

Let the first odd integer be x

And the other will be (x + 2)..

x(x + 2) - x/3 = 250

$$x^2 + 2x - x/3 = 250$$

$$3x^2 + 6x - x = 250*3$$

$$3x^2 + 5x = 750$$

$$3x^2 + 5x - 750 = 0$$

Solve it by using Quadratic Formula...

anonymous · Answer

two very nice ways of solving the problem... :)

agent47 · Answer

*had a typo lol i meant 250 not 50

anonymous · Answer

now there are three nice ways...:)

anonymous · Answer

Solve the following for n:$$(2n+1)(2n+3)-\frac{1}{3}(2n+1)=250$$n = 7

{2*7+1,2*7+3} -> {15,17}