Mathematics
7 Online
OpenStudy (anonymous):
what is the distance formula?
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OpenStudy (anonymous):
suppose you want to find the distance between two points (x1,y1) and (x2,y2)
the distance formula is
=sqrt((x1-x2)^2+(y1-y2)^2)
OpenStudy (anonymous):
\[d = \sqrt{(x2-x1)^{2} +(y2-y1)^{2} }\]
OpenStudy (chaise):
Which in essence is simply Pythagoras theorem, if you form an 'imaginary' triangle between the two points.
OpenStudy (anonymous):
okay i have to find the distance between (5,5) and (10,2)
OpenStudy (anonymous):
then take (5,5) as (x1,y1)
and (10,2) as (x2,y2) then put these values in require formula
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OpenStudy (anonymous):
is it 14?
OpenStudy (anonymous):
how did you get that?
OpenStudy (anonymous):
idkk.im not sure what the answer is
OpenStudy (anonymous):
did you just guess at 14? the instructions provided by the two posters are pretty clear...
OpenStudy (anonymous):
no i just didnt plug it in right.whats the answer then?
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OpenStudy (anonymous):
i can't directly give you the answer... but i can make you give me the answer....
OpenStudy (anonymous):
k?
OpenStudy (anonymous):
what's \(\large x_2-x_1= \) and \(\large y_2-y_1= \)
OpenStudy (anonymous):
2 and -3?
OpenStudy (anonymous):
no...
\(\large x_2-x_1= \) refers to subtracting the x coordinates... what are the x coordinates?
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OpenStudy (anonymous):
arent they 5 and 10?
OpenStudy (anonymous):
yes... now subtract those two x values...
OpenStudy (anonymous):
-5
OpenStudy (anonymous):
good. now
\(\large (x_2-x_1)^2=(-5)^2=25 \), agreed?
OpenStudy (anonymous):
yess
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OpenStudy (anonymous):
good... i want you to do the exact same thing with the y-coordinates....
find me \(\large (y_2-y_1)^2= \)
OpenStudy (anonymous):
its 9 right?
OpenStudy (anonymous):
correct... so in the distance formula:
\(\large d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}=\sqrt{25+9} \)
can you simplify it from here?
OpenStudy (anonymous):
is it 5.83?
OpenStudy (anonymous):
if that's what your calculator gave you for \(\large \sqrt{34} \), then yes...
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OpenStudy (anonymous):
yupp it did
OpenStudy (anonymous):
the exact way to write your answer is \(\large \sqrt{34} \)
OpenStudy (anonymous):
wasn't that better than guessing? :)
OpenStudy (anonymous):
it tells me to round my answer to the nearest tenth though
OpenStudy (anonymous):
oh.. ok....:)
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OpenStudy (anonymous):
thank you so much:)
OpenStudy (anonymous):
yw...:)
OpenStudy (anonymous):
can you help me find the midpoint of (7,9) and (12,11)
OpenStudy (anonymous):
it is equal to( x1+x2)/2,(y1+y2)/2.
here (x1,y1) is (7,9) and (x2,y2) is (12,11)
OpenStudy (anonymous):
midpoint =(7+12)/2,(9+11)/2
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OpenStudy (anonymous):
9.5,10?
OpenStudy (anonymous):
yes