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Mathematics 19 Online
OpenStudy (konradzuse):

A billboard d = 85 feet wide is perpendicular to a straight road and is 40 feet from the road (see figure). Find the point on the road at which the angle θ subtended by the billboard is a maximum. (Round your answer to two decimal places.) x = ft

OpenStudy (konradzuse):

OpenStudy (konradzuse):

tan(a) = 40/x tan(a + o) = (40+85)/x = 125/x

OpenStudy (konradzuse):

Now I'm stuck :P.

OpenStudy (paxpolaris):

take the arctan of bot sides... so that you can write an equation for \(\theta\) \[\theta=???\]

OpenStudy (paxpolaris):

\(\theta\) as a function of x

OpenStudy (konradzuse):

well rifght now I have tan(a+o).

OpenStudy (konradzuse):

I gotta get rid of the tan(a) huh..

OpenStudy (paxpolaris):

\[\large a= \tan^{-1} \left( 40 \over x \right)\] \[\large a+\theta = \tan^{-1} \left( 125\over x \right)\] \[\large\theta =(a+\theta)-a\]

OpenStudy (konradzuse):

so hmmm...

OpenStudy (konradzuse):

arctan(125/x) -arctan(40/x)?

OpenStudy (paxpolaris):

yeah

OpenStudy (konradzuse):

hmmm

OpenStudy (konradzuse):

I'm still confused :P.

OpenStudy (paxpolaris):

what part

OpenStudy (konradzuse):

what exactly we are doing lol :P. Maybe as we go along I'll get it..

OpenStudy (konradzuse):

Just no sure where this is going to end up...

OpenStudy (paxpolaris):

\[\Large \theta =\tan^{-1}\left( 125 \over x \right)-\tan^{-1}\left( 40 \over x \right)\] so... \[\Large {d \theta \over dx} = \dots?\]

OpenStudy (konradzuse):

seems like it's going ot be some UGLYness...

OpenStudy (paxpolaris):

iknow ... groan

OpenStudy (konradzuse):

125/(x^2 * 15625?)

OpenStudy (konradzuse):

err +

OpenStudy (konradzuse):

- (40/(x^2+1600)?

OpenStudy (konradzuse):

lol I guess there was more to this.... \[\frac{1210(x^2-50000)}{(x^2+1600) (x^2) (1562500)}\]

OpenStudy (konradzuse):

the fawk..

OpenStudy (paxpolaris):

i'm not good at that i used wolfram alpha you flipped the signs ... it should be -125/.... +40/...

OpenStudy (konradzuse):

so did I lol... Wolfman FTW!

OpenStudy (konradzuse):

Okies so I'm not retypijng that, lol link plz?

OpenStudy (konradzuse):

and now we solve for x which I'm not going to attempt :P.

OpenStudy (konradzuse):

actually... I think it'as sqrt(5000?)

OpenStudy (konradzuse):

yeah that works :P 70.71

OpenStudy (paxpolaris):

yes

OpenStudy (konradzuse):

now onto the next question, we must hurry!

OpenStudy (konradzuse):

:P

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