Ask your own question, for FREE!
Mathematics 20 Online
OpenStudy (anonymous):

True/False: One to one functions are invertible.

OpenStudy (anonymous):

I don't know what one to one function is...

mathslover (mathslover):

true in fact only one to one functions have an inverse

mathslover (mathslover):

If a function is not one-to-one, it does not have a true inverse. hence true

OpenStudy (anonymous):

A one-to-one function is a function in which one input is only paired with one output. For example, y=x^2 is not a one to one function because, say, both (1)^2 and (-1)^2 yield one. Actually, all functions are "invertible" but only one-to-one functions have inverses that are functions.

OpenStudy (anonymous):

True. And if you want to go further, by restricting the domain of f(x) you can make a function such as f(x)=x^2 invertible.

OpenStudy (anonymous):

Thanks everyone, I really do appreciate it but I'm trying to figure out why'd they used the word invertible though? Was that a trick?

OpenStudy (anonymous):

Thats an actual term. It means that you can invert the graph of a one-to-one function over the y-axis to get its inverse.

OpenStudy (anonymous):

You can read about function inverses. If a function turns an input x into an output y, then the inverse of that function maps y back to x. For example: y=x^2. If we restrict the domain of y=x^2 to values of x greater or equal to 0, then the inverse of y=x^2 is y=sqrt(x). For a value, say, 3. y=x^2 turns 3 into 9. However, y=sqrt(x) inverts, or turns 9 back into 3. You follow me?

OpenStudy (anonymous):

Okay @EdG I don't understand the last sentence you wrote. And yes @anhhuyalex

OpenStudy (anonymous):

So everything cool?

OpenStudy (anonymous):

My mistake. Graphically, a function and its inverse are symmetric with respect to the y-axis. So when you "flip" a function over the y-axis, the resulting graph is its inverse. It's basically what anhhuyalex said, i just made it more complicated. It helps when you are working with graphs instead of equations

OpenStudy (anonymous):

Oh, okay. Thanks so much everyone! I really do appreciate it :-). I'm preparing for my finals, sigh :(...

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!