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A simple combinatorics problem. Word 'SUCCESS'. Number of ways such that no two Ss and Cs are together.
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@eliassaab @blockcolder
my guess is 360....idk if i solved it rite....anyone??
360!?! :o How?
well its wrong sry!!
Of course it is.
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396 ?
Noway Dude
factorial of 6??
Nope
Stop guessing. Take your time and work on the problem.
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And for your information, this problem is not some challenge. I don't know how to do it. So you will have to show your work.
|dw:1340534838304:dw| can be interchange so that no S are together in only 2 ways........ |dw:1340534915656:dw| 6 spaces can be filled by 2 Es in ....6c3/2 ways...... |dw:1340534979616:dw|.. so final answer is 15
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