Question

Hey you guys, I need help with a geometry question, I just screen cap'd it so that way it would be easier.

Answer 1

Do you agree that \(\angle\)BDE and \(\angle\)DAC are equal?

Answer 2

They don't look like they're equal,

Answer 3

3-angle BDE=angleBEC-----------corresponding angle formed by two parrlel lines and a transwersal are equal

Answer 4

5-triangle BDEis similar to triangle BAC------ by AA similarity condition

Answer 5

sorry, angle BDE is equal to BAC and not BEC as misstyped by me

Answer 6

\(\angle\)BEC is a line with 180 degree and center point at E, unless I have the naming convention off?

Answer 7

And why don't you think \(\angle\)BAC, \(\angle\)BDE, and \(\angle\)DAC are equal?

Answer 8

Because of SAS?

Answer 9

Compare against the angles on the right. If you add the ones on the right left and top you form a triangle, now matter which one you choose.

\(\triangle\) = 180\(^o\) = \(\angle\alpha\) + \(\angle\beta\)+\(\angle\gamma\)

It doesn't matter what the measures of each are, the sum has to be 180 if it's a 2D triangle like this.

Just something to consider in your proofs

Answer 10

I think they're trying to force you to cite specific proof-related axioms and theorems though, seeing as they kind of drew up all the steps and the blanked two of them out... Remembering names isn't a strength with me, I'd have to look it up all over again.

Answer 11

Yeah me neither, I can't remember names to save my life.

Answer 12

You have a book though don't you? :-D

Answer 13

Nah, I'm doing virtual school and I had to give it back once I switched out.

Answer 14

Sorry, my computer lagged out and my comment never posted.wwww

Answer 15

http://www.mathnstuff.com/math/spoken/here/2class/260/trans.htm

Answer 16

That's basically what this kind of problem is, but they combined it with a triangle.

Answer 17

Alternate interior angles, or alternate exterior angles, are congruent (equal)