Question

Choose the correct simplification of

Answer 1

Wouldn't it just be x^4?

Answer 2

\[x^m/x^n = x^{m-n}\]

Here, m = 7 and n = 3..

Solve and get the answer..

Answer 3

i still dont get it

Answer 4

All you do it subtract the exponents. 7-3 is 4, so it's x^4.

Answer 5

Can I suggest him how to do it in a simple way?

Answer 6

Sure.

Answer 7

\( \color{Black}{\Rightarrow \Large {x^7 \over x^3} = {\cancel{x \cdot x \cdot x} \cdot x \cdot x \cdot x \cdot x \over \cancel{x \cdot x \cdot x}} = x \cdot x \cdot x \cdot x = x^4}\)

The property that they stated is based on this ^

Answer 8

Simple way of looking at it^ Google laws of indices for more examples of this type of stuff.

Answer 9

im adding the powers together from top to bottom is that a good way to do it?

Answer 10

?

Answer 11

You just subtract the powers.

Answer 12

\[\huge{\frac{x^7}{x^3}=x^{(7-3)}=x^4}\]

Answer 13

Yes..

Answer 14

Well see mine if you have a question like "why subtract?"

Answer 15

here is the proof of \(\huge{\frac{a^b}{a^c}=a^{b-c}}\)

u can write it as :
\[\huge{a^b*a^{-c}}\]
\[\huge{a^{b+(-c)}=a^{b-c}}\] hence proved

Answer 16

or u can do like that what @ParthKohli did

Answer 17

Check this out, plenty of examples there. http://www.algebra.com/algebra/homework/Exponents/change-this-name15736.lesson