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Mathematics 19 Online
OpenStudy (anonymous):

Determine the conditions that will make ΔZWU ≅ ΔVUW. Which of the following statements will guarantee that ΔZWU ≅ ΔVUW?

OpenStudy (anonymous):

nope

OpenStudy (anonymous):

OpenStudy (anonymous):

there we go

OpenStudy (anonymous):

Quadrilateral ZWVU is a square. Line segment ZW is parallel to line segment UV ∡ZUV and ∡WVU measure 90°. Line segment ZU ≅ Line segment WV

OpenStudy (anonymous):

any tips?

OpenStudy (anonymous):

Alright. You remember the 5 ways that triangles can be proven congruent right?

OpenStudy (anonymous):

AAS, SAS, SSS, ASA, or CPCTC?

OpenStudy (anonymous):

Close. AAS, SAS, SSS, ASA, or HL

OpenStudy (anonymous):

whats HL?

OpenStudy (anonymous):

Hypotenuse Leg

OpenStudy (anonymous):

Never heard of that one before.

OpenStudy (anonymous):

Oh ok.

OpenStudy (anonymous):

Now, one of those choices would make all the other statements true. Which one is that?

OpenStudy (anonymous):

can you guide me through this step by step?

OpenStudy (anonymous):

ehh

OpenStudy (anonymous):

hold up

OpenStudy (anonymous):

Quadrilateral ZWVU is a square?

OpenStudy (anonymous):

In order to be a square, all of those other things have to be true

OpenStudy (anonymous):

Yup. That's the correct answer. If you want a step by step, hold on.

OpenStudy (anonymous):

well

OpenStudy (anonymous):

A square has 90 degree angles, parallel sides

OpenStudy (anonymous):

and congruent sides

OpenStudy (anonymous):

And a square encompasses all of these properties

OpenStudy (anonymous):

right?

OpenStudy (anonymous):

can you help me out with another after this?

OpenStudy (anonymous):

If it's a square look:|dw:1340576755717:dw| You can use a plethora of theorems to prove these congruent. For instance, being a square makes two of the sides of the triangle congruent. Then the hypotenuse is congruent because of the reflexive property. Then, all right angles are congruent. Finally, alternate interior angles prove the other angles congruent.

OpenStudy (anonymous):

Sure.

OpenStudy (anonymous):

k

OpenStudy (anonymous):

ehh

OpenStudy (anonymous):

Which fact could you use to help prove that ΔABDΔACB using Side-Side-Side?

OpenStudy (anonymous):

∠ACB ≅ ∠DBA Line segment DB over line segment AD is equal to line segment BC over line segment AB Line segment AD is congruent to line segment CB. ∠BAC + ∠BCA = 90˚

OpenStudy (anonymous):

tips?

OpenStudy (anonymous):

forgot to give medal

OpenStudy (anonymous):

k

OpenStudy (anonymous):

I though AD equals CB

OpenStudy (anonymous):

I doubt AD equals CB

OpenStudy (anonymous):

thats just common sense

OpenStudy (anonymous):

k

OpenStudy (anonymous):

you there cal?

OpenStudy (anonymous):

cal?

OpenStudy (anonymous):

∠ACB ≅ ∠DBA

OpenStudy (anonymous):

you don't prove angles in SSS

OpenStudy (anonymous):

Are you proving them similar? Because the symbol is missing.

OpenStudy (anonymous):

∠BAC + ∠BCA = 90˚

OpenStudy (anonymous):

thats out too

OpenStudy (anonymous):

I'm proving them similar through SSS

OpenStudy (anonymous):

Meh. Hold on.

OpenStudy (anonymous):

Line segment DB over line segment AD is equal to line segment BC over line segment AB

OpenStudy (anonymous):

That seems to be the only logical answer

OpenStudy (anonymous):

I think so too. THis kind of problem looks like the kind that's the three right triangles and the geometric mean. I think it's the second one too.

OpenStudy (anonymous):

and your problem solving rank is lifesaver

OpenStudy (anonymous):

I'll go with you

OpenStudy (anonymous):

Mine is still only hatchling

OpenStudy (anonymous):

k

OpenStudy (anonymous):

a few more?

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