10^(x+1)=3e^(5-x)

Question

10^(x+1)=3e^(5-x)

anonymous · Answer

this is what i got so far, not sure if I'm going the right way

campbell_st · Answer

I think you have a problem in that you appear to have difference logs on different sides of the equation

anonymous · Answer

I don't think is a trick question, i know I have e and log, which don't really correlate, but is possible to find log(e(1)) so there has to be an answer

anonymous · Answer

e^ ust to ln not log

campbell_st · Answer

my solution would be 

$$\ln(\frac{10^{x+1}}{3} )=  5 - x$$

after taking the base e log of both sides

which can be written 

$$(x +1)\ln(10) - \ln(3) = 5 - x$$

anonymous · Answer

ok, i see what you mean. ill work it that way

anonymous · Answer

@EdG your solution is right

anonymous · Answer

i got $$x=(5loge+\log3-1)/(1+loge)$$
which is roughly 1.15. It came out correct.
Thanx for the help anyway

anonymous · Answer

almost done

anonymous · Answer

i should use ln instead though, I'm pretty sure my professor would prefer that and she is pretty anal about things like that