The figure below shows rectangle ABCD. The two-column proof with missing statement proves that the diagonals of the rectangle bisect each other.
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OpenStudy (anonymous):
OpenStudy (anonymous):
Statement:
ABCD is a rectangle
OpenStudy (anonymous):
Reason:
Given
OpenStudy (anonymous):
Statement: Line segment AB and line segment CD are parallel
OpenStudy (anonymous):
Reason:
Definition of a Parallelogram
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OpenStudy (anonymous):
Line segment AD and line segment BC are parallel
OpenStudy (anonymous):
Reason: Definition of a Parallelogram
OpenStudy (anonymous):
Statement:
Yet to be filled in
OpenStudy (anonymous):
Reason:
Alternate interior angles theorem
OpenStudy (anonymous):
Line segment BC is congruent to line segment AD
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OpenStudy (anonymous):
Reason:
Definition of a parallelogram
OpenStudy (anonymous):
Statement:
Angle ADB is congruent to angle CBD
OpenStudy (anonymous):
Reason:
Alternate interior angles theorem
OpenStudy (anonymous):
VADE is congruent to VCBE
OpenStudy (anonymous):
Reason:
ASA Postulate
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OpenStudy (anonymous):
Line segment BE is congruent to line segment DE
OpenStudy (anonymous):
Wait, where did V come from?
OpenStudy (anonymous):
Reason:
CPCTC
OpenStudy (anonymous):
I don't know :(
OpenStudy (anonymous):
let me keep posting(later I want you to answer my question about Gengar :))
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OpenStudy (anonymous):
Line segment AE is congruent to line segment CE
OpenStudy (anonymous):
Reason:
CPCTC
OpenStudy (anonymous):
Statement:
Line segment AC bisects line segment BD
OpenStudy (anonymous):
Reason:
Definition of a bisector
OpenStudy (anonymous):
Any tips?
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OpenStudy (anonymous):
This is a fill in the blank answer
OpenStudy (anonymous):
Statement: Yet to be filled in
a few moments ago
55
luisz
Medals 0
Reason: Alternate interior angles theorem
OpenStudy (anonymous):
∡ABD ≅ ∡DBC
∡CAD ≅ ∡ACB
∡BDA ≅ ∡BDC
∡CAB ≅ ∡ACB
OpenStudy (anonymous):
Here are the choices...
OpenStudy (anonymous):
Tips?
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OpenStudy (anonymous):
Alright. Knowing it's ASA and that one pair of the angles is congruent along with a side, which pair of angles have to be congruent to prove the triangle congruent?
OpenStudy (anonymous):
Hmmmm
OpenStudy (anonymous):
give me a minute
OpenStudy (anonymous):
ahhh
OpenStudy (anonymous):
this cannot be right:
∡ABD ≅ ∡DBC
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OpenStudy (anonymous):
Their vertex is the exact same
OpenStudy (anonymous):
right?
OpenStudy (anonymous):
Are am I wrong?
OpenStudy (anonymous):
Because don't alternate interior angles have different vertices?
OpenStudy (anonymous):
you there?
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OpenStudy (anonymous):
If so, I could also knock out ∡BDA ≅ ∡BDC
OpenStudy (anonymous):
I guess so? Look for alternate interior angles otherwise known as a Z shape.
OpenStudy (anonymous):
From the images I've seen, the vertices appear to be different
OpenStudy (anonymous):
The vertices are from different angles of the two lines
OpenStudy (anonymous):
Lets say we have to lines cut by a transversal
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OpenStudy (anonymous):
The first line has vertex angle A and the other line has vertex angle B
OpenStudy (anonymous):
You see where I am going?
OpenStudy (anonymous):
brb
OpenStudy (anonymous):
k
OpenStudy (anonymous):
I could be mistaken though
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