Question

solve using completing the square leave in simplified form
help plz
3x^2-6x=27

Answer 1

step one, divide by 3 so the leading coefficient is 1
you will get
\[x^2-2x=9\]

Answer 2

step 2 take half the coefficient of the \(x\) term, which his this case is \(-1\) square it and get 1 and write
\[(x-1)^2=9+1=10\]

Answer 3

step 3 take the square root of both sides. don't forget the \(\pm\) to get
\[x-1=\pm\sqrt{10}\]

Answer 4

and the last step is to solve for \(x\) by adding one to both sides to get
\[x=1\pm\sqrt{10}\]

Answer 5

that sign that you made i dont know about that ive never actually learned the basics of this or the signs

Answer 6

you mean \(\pm\) ?

Answer 7

yeah does that just mean not equal too?

Answer 8

no it means "plus or minus"

Answer 9

you can write instead \(x=1+\sqrt{10}\) or \(x=1-\sqrt{10}\)

Answer 10

ohhh so its a + sign and then under that itz minus

Answer 11

rigjt

Answer 12

i didnt know that thank you

Answer 13

yw

Answer 14

:)