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Mathematics 10 Online
OpenStudy (anonymous):

A funnel with a height of 3.67 inches is shown below.The funnel has a diameter of 1.87 inches that includes a wall that is 0.125 inches thick. What is the maximum volume of the funnel rounded to the nearest hundredth?

OpenStudy (anonymous):

OpenStudy (anonymous):

K

OpenStudy (anonymous):

I am trying to figure what the diameter is

OpenStudy (anonymous):

I first though about subtracting .125 from 1.87

OpenStudy (anonymous):

that gives us 1.745

OpenStudy (anonymous):

Um, the diameter is given to you...

OpenStudy (anonymous):

includes a wall that is 0.125 inches thick

OpenStudy (anonymous):

What do I do with the wall thing?

OpenStudy (anonymous):

Is it meant for confusion?

OpenStudy (anonymous):

That's a bit of reasoning that I'm just gonna guess a little bit on. You remmeber the formulas for surface area and volume of a cone?

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

so wait

OpenStudy (anonymous):

Well, rather lateral area.

OpenStudy (anonymous):

Find the volume and lateral area and then post it here.

OpenStudy (anonymous):

If I found the volume, the area would be approximately 3.36

OpenStudy (anonymous):

Here are the answer choices

OpenStudy (anonymous):

2.52 in3 2.22 in3 7.57 in3 3.36 in3

OpenStudy (anonymous):

If I have to add lateral area, it is definitely going to be 7.57

OpenStudy (anonymous):

What's the volume of the figure without the thickness?

OpenStudy (anonymous):

Lateral area is aprroximately 21.56 :(

OpenStudy (anonymous):

Without thickness

OpenStudy (anonymous):

approximately 2.93

OpenStudy (anonymous):

Which is not an answer choice

OpenStudy (anonymous):

you there?

OpenStudy (anonymous):

Well, I'm a bit stumped

OpenStudy (anonymous):

well

OpenStudy (anonymous):

is it 3.36?

OpenStudy (anonymous):

what say you smod?

OpenStudy (anonymous):

hmm

OpenStudy (anonymous):

Well, what is the maximum volume of the cone?

OpenStudy (anonymous):

Wouldn't it be 3.36?

OpenStudy (anonymous):

Or does the wall restrict it?

OpenStudy (anonymous):

what say you, goforit?

OpenStudy (anonymous):

if the wall did restrict the volume from being 3.36, the answer would be 2.92 :/

OpenStudy (anonymous):

http://www.youtube.com/watch?v=l_KW_pRkEzg

OpenStudy (anonymous):

V = 3.35 - 1.4376 = 1.9124

OpenStudy (anonymous):

Which is not an answer...

OpenStudy (anonymous):

hmmm

OpenStudy (anonymous):

ehh

OpenStudy (anonymous):

Its the wall that bugs me

OpenStudy (anonymous):

But if we did not include the wall, the answer would be 3.36

OpenStudy (anonymous):

and the video does not include the thickness of a wall...

OpenStudy (anonymous):

thats whats puzzling us

OpenStudy (anonymous):

it's multiple choice right?

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

1.069468583π - 0.442632721π = 1.96926 Darn it... Still no correct answer...

OpenStudy (anonymous):

2.52 in3 2.22 in3 7.57 in3 3.36 in3

OpenStudy (anonymous):

to the nearest hundereth also right?

OpenStudy (anonymous):

You sure you wrote down the radius and height correctly? You sure it didn't say radius or slant height?

OpenStudy (anonymous):

I mean diameter.

OpenStudy (anonymous):

The funnel has a diameter of 1.87 inches that includes a wall that is 0.125 inches thick. What is the maximum volume of the funnel rounded to the nearest hundredth?

OpenStudy (anonymous):

A funnel with a height of 3.67 inches is shown below.

OpenStudy (anonymous):

A funnel with a height of 3.67 inches is shown below.

OpenStudy (anonymous):

the wall kind of makes this weird

OpenStudy (anonymous):

I know

OpenStudy (anonymous):

Does the wall matter?

OpenStudy (anonymous):

We need KingGeorge or Phi for this

OpenStudy (anonymous):

with the wall you said 2.29 or something correct?

OpenStudy (anonymous):

k, Moha is going to help us

OpenStudy (anonymous):

nope, 2.92

OpenStudy (anonymous):

moha

OpenStudy (anonymous):

can you help us out with this problem

OpenStudy (anonymous):

moha?

OpenStudy (anonymous):

even if the answer was 2.92 the closest to that is 2.52 and that doesn't really seem as correct I mean 3.36 is probably more obvious although it still begs the question, is the wall important

OpenStudy (anonymous):

Hold on. I might have just figured it out. :)

OpenStudy (anonymous):

k, but lets see what Moha thinks

OpenStudy (anonymous):

V = 2.52153

OpenStudy (anonymous):

Moha is thinking, guys

OpenStudy (anonymous):

how did you find out about 2.52?

OpenStudy (anonymous):

Look. The purpose of the wall is to lower the radius.

OpenStudy (anonymous):

I knew that

OpenStudy (anonymous):

So the radius is 0.81

OpenStudy (anonymous):

but I lowered the diameter instead...

OpenStudy (anonymous):

Lower the diameter twice

OpenStudy (anonymous):

The diameter goes through the wall twice remember?

OpenStudy (anonymous):

I just divided the diameter by 2 and lowered the radius by .125

OpenStudy (anonymous):

That gave the same answer

OpenStudy (anonymous):

Yes.

OpenStudy (anonymous):

2.52153337

OpenStudy (anonymous):

There we go :)

OpenStudy (anonymous):

Boy, that was a doozy.

OpenStudy (anonymous):

for sure

OpenStudy (anonymous):

it was interesting

OpenStudy (anonymous):

The answer was right under our noses

OpenStudy (anonymous):

You deserve a medal :D!!!!!!!!!!!!!!!!!!

OpenStudy (anonymous):

lol. Yup. I was having a brief brain fart lol

OpenStudy (anonymous):

same

OpenStudy (anonymous):

look guys i think somthing wrong with the queation

OpenStudy (anonymous):

what?

OpenStudy (anonymous):

you sure?

OpenStudy (anonymous):

what say you smod?

OpenStudy (anonymous):

Our last resort is DA Panic!!!!!!!!!!!!!!!!!!!!!!!

OpenStudy (anonymous):

When you actually think about it @moha_10 it works because imagine the cone with the radius restriction. It gives you an area without the wall inside.|dw:1340591985209:dw|

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