Let X be a normal random variable with its mean equal to 40 and standard deviation equal to 5.find the following probablilties for this normal distribution a)P(x>55) B)P(x<49)
find the z scores
i did N i got 3
in my data booklet there is no z score at the value of three
3?
yes
each z score is one standard deviation from the mean
i don't get you...how?
\[z=\frac{X-\mu}{\sigma}=\frac{55-40}{5}=3\]
but then @kropot72 in a data booklet there is not a score with the value of 3
Use the empirical rule: About 99.73% of the area of the normal distribution is included within a distance of plus and minus 3 standard deviations from the mean.
i've never heard of that formula before..pls show me what you mean.
@jazrio you must have a weird table if you don't have a value of 3 in your table
a lot of the tables go up to 3.49
but @Zarkon my teacher gave me the table and she said that only this values will be given the rest you'll have to find out....ex:the negative z scores
my one stops at 2.9 only
you only have half of the normal table?
weird
kropot72 method will give you the answer then
but i dunno how to do it
can you help me pls
it would be weird to show you a way that your instructor had not taught.
yeah but @Zarkon you see my instructor gave me this question long time ago but i don't recall which method she used
100 - 99.73 = 0.27% of the area lies outside the plus and minus 3 standard deviations from the mean. We are interested in only the upper tail of the normal distribution curve. Therefore the value 0.27% must be halved.
@kropot72 sorry...i can't visualise
BTW I have a z table that goes up to z = 4. That table gives 0.1% for z = 3.
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