Question

Plz help:)

Answer 1

If \[2x-2x-1=4\] then \[x^x\] is equal to

Answer 2

@ParthKohli plz help:)

Answer 3

Oh! i m sorry. It's 2x-2^x-1

Answer 4

@Sriram x-1 is the power of 2

Answer 5

Can you write the question once again in more correct form??

Answer 6

& the answer is 27.

Answer 7

\[2x-2^{x}-1=4\]
Is that the original equation?

Answer 8

no, the original equation is\[2^x-2^{x-1}=4\]

Answer 9

8-4=4

Answer 10

4 can be rewritten as 2^2.
2^x can be rewritten as x*2^(x-1).

Answer 11

\[2^x - 2^{x-1} = 4\]

From this equation by trail let me check for x = 3

\[2^3 - 2^2 = 4\]

\[4 = 4\]

So, x = 3 satisfies this equation..

\[x^x = 3^3 = 27\]

Answer 12

\[2^x-2^{x-1}=4 \\ 2^x-\frac{2^x}{2}=4 \\ \frac{2^x}{2}=4\\ 2^x=8 \\ x=3\]

Answer 13

then
\[x^x=3^3=27\]

Answer 14

K! I have gt it .
Thanx, a lot to everyone:)

Answer 15

@mukushla I want to know once again how you found the value for x above??

Answer 16

Can you explain your third step???

Answer 17

& @Sriram i m sorry.

Answer 18

Alternate way to do it:
\[2^{x}-2^{x-1} = 4\]
\[2*2^{x-1}-1*2^{x-1} = 2^{2}\]
\[2^{x-1}(2-1) = 2^{2}\]
\[2^{x-1}(1) = 2^{2}\]
\[2^{x-1} = 2^{2}\]
X-1=2
X=3

Answer 19

@waterineyes
\[2^x-\frac{2^x}{2}=2^x(1-1/2)=\frac{2^x}{2} \\ \because 2^{x-1}=\frac{2^x}{2^1}\]

Answer 20

Yes, I got it thanks buddy...