Problem for you. If [x] represents the greatest integer less than or equal to x. Find the number of integral solutions of [x/101] = [x/99]
[x] is floor function right??
Umm. Yes. Is[1.4]= 1 ?
x=0-98 x=101-(99x2-1) x=101x2-(99x3-1) x=(101x3) - (99x4-1) ..
that would be positive integer solutions ... I think we need for negative side too.
I'm not getting what youre doing. A little explanation?
I'm finding the domain of x. first case, 0 to 98, then 101 to (99x2-1) ... and so on. The domain is shrinking.
is answer 2x2450?
Close. Very close.
4902 ?? i guess 4902 because it is symmetric both on negative and positive.
Nope:)
is it 4901??
possibly 4903 adding the last number on both sides plus adding 0
HAha. It's 5000.
I see http://www.wolframalpha.com/input/?i=%282%2B4%2B..%2B100%29+%2B+%282%2B4%2B6%2B..%2B98%29 on the negative side, [-0.5] = 0 .. that gives extra hundred on the negative side.
Excellent. Well done.As usua. :)
Join our real-time social learning platform and learn together with your friends!