Question

I really need help with this question

Answer 1

I think I use a^2 + b^2 = C^2 I just don't know what numbers to place where

Answer 2

For the radius, you would do a^2 + b^2 = c^2 with CM & OM

Answer 3

You know that CD is 44 so CM is half of that value.

Answer 4

so i have to find c^2

Answer 5

Yes

Answer 6

c2 would be the radius

Answer 7

Okay so I got sqrt 884 is that tight

Answer 8

YES √884 is correct for the radius. For part b, it is again the pythagorean theorem. use the radius that you found & the value for ON, which is 19. this time you are not solving for c^2, since you already found that (the radius) you are solving for b^2.

Answer 9

so it would be 19^2 + b^2 = sqrt884

Answer 10

Yeah, now algebraically solve for b^2.

Answer 11

okay this is were I get confused what do I do after 361 + b^2 = sqrt 884

Answer 12

It is √(884)^2 btw!!! So that actually just = 884!!!

Answer 13

oh thank you

Answer 14

so the answer is sqrt523

Answer 15

After you get 361 + b^2 = 884, you have to subtract 361 to get the variable (b^2) alone. The golden rule of algrebra is what you do to one side, you must do to the other so subtract 361 fro 884

Answer 16

Yeah, sorry I didn't realize you already posted the final answer! That's right!

Answer 17

thank now can you help me with the last one do I still use a^2 + b^2 = C^2

Answer 18

No! Since you already know half of EF (√523) you just multiply by 2

Answer 19

multiple 523 by two or the sqrt

Answer 20

all of it. (√523) x 2 = 45.74

Answer 21

Thank you so much for your help can you help with one more

Answer 22

uh sure haha

Answer 23

Here it is

Answer 24

I can't figure out what Theorem to use here

Answer 25

Oh I'm sorry! I don't really remember how to do those, that was so long ago in geometry lol, like I'm doing AP Calc now. You should post it as a new question & you'll get someone else to help! Sorry!

Answer 26

thank you