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Mathematics 7 Online
OpenStudy (anonymous):

Circle P is tangent to the x-axis and the y-axis. If the coordinates of the center are (r, r), find the equation of the line containing the chord (put your answer in standard form.) answer has to be in this format: x + ___ = ___

OpenStudy (anonymous):

OpenStudy (anonymous):

chord?

OpenStudy (anonymous):

@jim_thompson5910 help

OpenStudy (anonymous):

you mean passing through the center of the circle?

OpenStudy (anonymous):

idont understand the question either

OpenStudy (anonymous):

chords there are infinte number of them, but what they have in commun is, that they all go through the center

jimthompson5910 (jim_thompson5910):

no, a chord that goes through the center is known as the diameter...but a chord doesn't have to go through the center.

jimthompson5910 (jim_thompson5910):

a chord is simply a line segment that has endpoints on the circle

OpenStudy (anonymous):

so then any line that cross circle is ok

jimthompson5910 (jim_thompson5910):

maybe they want a chord that has the endpoints where the tangent points are?

OpenStudy (anonymous):

so would it be x+ r=0

jimthompson5910 (jim_thompson5910):

these instructions seem like they're missing something

OpenStudy (anonymous):

no, wait....

OpenStudy (anonymous):

i copied and now pasted it :Circle P is tangent to the x-axis and the y-axis. If the coordinates of the center are (r, r), find the equation of the line containing the chord (put your answer in standard form.)

OpenStudy (anonymous):

x + =

OpenStudy (anonymous):

the x,y coordinates of the circle are positive and bounded by 2r

jimthompson5910 (jim_thompson5910):

hmm like I said, something seems to be missing If they want the chord that connects the tangent points, then the equation is x+y = r This is because you can solve for y to get y = -x + r And you'll see that it has a y-intercept of (0,r). This is one tangent point. Also, when you plug in y = 0 and solve for x, you get x = r So it also has an x-intercept of (r,0), which is another tangent point.

jimthompson5910 (jim_thompson5910):

But the issue is that it could be any chord really

OpenStudy (anonymous):

ithink they just want x+y=r

OpenStudy (anonymous):

just the first equation

jimthompson5910 (jim_thompson5910):

maybe, but without clearer instructions, it's anyone's guess really

OpenStudy (anonymous):

yeah.. could you help me with this last one = Circle P is tangent to the x-axis and the y-axis. If the coordinates of the center are (r, r), find the slope of the line through the origin and the center. (same picture above) =slope=

jimthompson5910 (jim_thompson5910):

The origin is the point (0,0) The center is the point (r,r) So you want to find the slope of the line through the points (0,0) and (r,r)

jimthompson5910 (jim_thompson5910):

So... m = (y2 - y1)/(x2-x1) m = (r - 0)/(r - 0) I'll let you finish this off

OpenStudy (anonymous):

1 :)

jimthompson5910 (jim_thompson5910):

you got it

OpenStudy (anonymous):

thanks!!:D

jimthompson5910 (jim_thompson5910):

yw

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