Circle P is tangent to the x-axis and the y-axis. If the coordinates of the center are (r, r), find the equation of the line containing the chord (put your answer in standard form.) answer has to be in this format: x + ___ = ___
chord?
@jim_thompson5910 help
you mean passing through the center of the circle?
idont understand the question either
chords there are infinte number of them, but what they have in commun is, that they all go through the center
no, a chord that goes through the center is known as the diameter...but a chord doesn't have to go through the center.
a chord is simply a line segment that has endpoints on the circle
so then any line that cross circle is ok
maybe they want a chord that has the endpoints where the tangent points are?
so would it be x+ r=0
these instructions seem like they're missing something
no, wait....
i copied and now pasted it :Circle P is tangent to the x-axis and the y-axis. If the coordinates of the center are (r, r), find the equation of the line containing the chord (put your answer in standard form.)
x + =
the x,y coordinates of the circle are positive and bounded by 2r
hmm like I said, something seems to be missing If they want the chord that connects the tangent points, then the equation is x+y = r This is because you can solve for y to get y = -x + r And you'll see that it has a y-intercept of (0,r). This is one tangent point. Also, when you plug in y = 0 and solve for x, you get x = r So it also has an x-intercept of (r,0), which is another tangent point.
But the issue is that it could be any chord really
ithink they just want x+y=r
just the first equation
maybe, but without clearer instructions, it's anyone's guess really
yeah.. could you help me with this last one = Circle P is tangent to the x-axis and the y-axis. If the coordinates of the center are (r, r), find the slope of the line through the origin and the center. (same picture above) =slope=
The origin is the point (0,0) The center is the point (r,r) So you want to find the slope of the line through the points (0,0) and (r,r)
So... m = (y2 - y1)/(x2-x1) m = (r - 0)/(r - 0) I'll let you finish this off
1 :)
you got it
thanks!!:D
yw
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