Question

Find the area of the region bounded by the graphs of the equation y = x^3 + x [4,0]

Answer 1

I don't think I do an integration?

\[\int\limits_{0}^{4} x^3 +x?\]

Answer 2

we have to do integration here

Answer 3

oh okay was my setu correct?

Answer 4

yes correct!!:)

Answer 5

do we have to find the area between x=0 to x=4?

Answer 6

so x^4/4 + x^2/2

Answer 7

x = 4 y =0

Answer 8

Find the area of the region bounded by the graphs.

Answer 9

\[\int\limits\limits_{0}^{4} x^3 +x\]
is the area under x=0 and x=4

Answer 10

ok so what do I do for x = 4 and y = 0?

Answer 11

ok... soo

Answer 12

:)

Answer 13

what do you mean by [4,0]?

Answer 14

HElloooooo are you there?

Answer 15

I'm sorry.

Answer 16

[4,0] meaniong x =4 y = 0.

Answer 17

ohh ok

Answer 18

So just integrate that equation from 0 to 4.

Answer 19

So like I posted from the start? lawls...

Answer 20

Int(x^3+x,x,0,4)=x^4/4+x^2/2=4^3+8

Answer 21

\[\int\limits_{0}{4} \frac{x^4}{4} \frac{x^2}{2}\]

Answer 22

NOOOOOOOOOOOOOOOOOO

Answer 23

\frac{x^4}{4} \frac{x^2}{2}\[ \frac{4^4}{4} \frac{4^2}{2} = 4^ \frac{^2}{2}\]

Answer 24

nooo? :(