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Mathematics 8 Online
OpenStudy (anonymous):

anyone good in chemistry?

OpenStudy (anonymous):

i am a lil depends on wat it is

OpenStudy (anonymous):

How many grams of Br2 are needed to react completely with 19.6 grams of Al? Al + Br2 AlBr3 Be sure to balance the equation. 38.7 grams 43.6 grams 87.1 grams 174 grams

OpenStudy (anonymous):

or this one? When 36 grams of aluminum carbide react with an excess of water, as shown in the unbalanced chemical equation below, how many moles of aluminum hydroxide will be produced? Al4C3 + H2O Al(OH)3 + CH4 0.25 moles 0.50 moles 1.0 moles 2.0 moles

OpenStudy (anonymous):

do u kno how to balance the equation?

OpenStudy (anonymous):

yes i dont get how to get the amount needed

OpenStudy (anonymous):

ohk this is a mass mass problem hold on let me refresh my memory

OpenStudy (anonymous):

im looking at the first one

OpenStudy (anonymous):

okay :)

OpenStudy (anonymous):

u have 3 steps 1.change grams to moles 2.do mole mole calculations 3.change answer to grams

OpenStudy (anonymous):

First find the moles of Al and use mole ratio from the balanced equation to find the moles of Br2. The moles of Al should be (mass/mw) 19.6g/26.98=0.726moles . From the mole ratio 2Al:3Br2. therfore you have 1.089moles of Br2. Then find the mass of Br (moles*mw) 1.089*(79.904*2)=174g .hope this helps ..:)

OpenStudy (anonymous):

it helps to write the balenced equation and then write wat u have and wat ur looking for

OpenStudy (anonymous):

thank you that was a really good explanation

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