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OpenStudy (anonymous):
How many moles of Ca3 (PO4)2 can be formed when 1.9 moles of CaCO3 react with 2.7 moles of FePO4?
CaCO3 + FePO4 Ca3 (PO4)2 + Fe2 (CO3)3
Be sure to balance the equation.
0.63 moles
1.3 moles
5.4 moles
5.7 moles
OpenStudy (anonymous):
gotcha covered izzy
OpenStudy (anonymous):
i need a yield sign tho
OpenStudy (anonymous):
first you need to figure out which one is the limiting reactant
OpenStudy (anonymous):
do this by finding how many moles of Calcium Phosphate you can make with each compound
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OpenStudy (anonymous):
how do i do that haha?
OpenStudy (anonymous):
wouldnt it be the same number though?
OpenStudy (anonymous):
yeah however after looking at your equation
OpenStudy (anonymous):
it is not balanced
you must balance it first
OpenStudy (anonymous):
do you know how to do this
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OpenStudy (anonymous):
do you know how to do this? every element has to have the same number of atoms on each side
OpenStudy (anonymous):
ok let me see
OpenStudy (anonymous):
3 CaCO3 + 2 FePO4 Ca3(PO4)2 + Fe2(CO3)3 ?
OpenStudy (anonymous):
that looks correct
OpenStudy (anonymous):
alright so now try this again
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