Question

pleaseeee? When 36 grams of aluminum carbide react with an excess of water, as shown in the unbalanced chemical equation below, how many moles of aluminum hydroxide will be produced?

Al4C3 + H2O Al(OH)3 + CH4

0.25 moles

0.50 moles

1.0 moles

2.0 moles

Answer 1

first find the molar mass of aluminum carbide. Al * 4 + C * 3. then take the mass divide by the molar mass. be sure to check the unit

Answer 2

i got 35.9

Answer 3

ok first lets start with balancing reaction equation:

Al4C3 + 12 H2O --> 4 Al(OH)3 + 3 CH4

now we can start to calculate, and first step is to calculate the given amount of Al4C3 from grams in moles:
n= m/M
n(Al4C3) = m(Al4C3)/M(Al4C3) = 36 g / 143,953 g mol-1
n(Al4C3) = 0,25 mol

now we need to take a look at balanced reaction and find out the ratio:
n(Al(OH)3)/n(Al4C3) = 1/4
n(Al(OH)3)= 4/1 * n(Al4C3) = 4 * 0,25mol = 1,0 mol