3) At the low point in it swing, a pendulum bob with a mass of 0.19 kg has a velocity of 4.53 m/s.

(a.) What is its kinetic energy at the low point?

(b.) Ignoring air resistance, how high will the bob swing above the low point before reversing direction?

Question

3) At the low point in it swing, a pendulum bob with a mass of 0.19 kg has a velocity of 4.53 m/s.

(a.) What is its kinetic energy at the low point?

(b.) Ignoring air resistance, how high will the bob swing above the low point before reversing direction?

anonymous · Answer

Kinetic energy is given by, E= (1/2) m v^2
E= (1/2) (0.19)(4.53^2) = 1.949 = 1.95J approx.

Loss in kinetic energy = Gain in potential energy
1.949 = mgh 
1.949 = (0.19)(9.81)(h)
h= 1.0459m = 1.05m approx.