Question

Divide and express the result in standard form:

9i
-----
6-8i

Answer 1

multiply top and bottom by the conjugate of the denominator. the conjugate of \(a+bi\) is \(a-bi\)

this works because \(a+bi)(a-bi)=a^2+b^2\) a real number
start with
\[\frac{9i}{6-8i}=\frac{9i}{6-8i}\times \frac{6+8i}{6+8i}\]

Answer 2

\[(36-27i)/-14\]

Answer 3

the denominator will be \(6^2+8^2=100\) and the numerator will be whatever you get when you multiply

Answer 4

be careful, because it is not the answer given above