Help please?

Question

Help please?

anonymous · Answer

Remember:
When:
$$Log_b (a) = x$$

Then:

$$b^x = a$$

In first question:

Firstly add 5 both the sides and tell me what you got??

anonymous · Answer

Sorry add x both the sides..

jiteshmeghwal9 · Answer

$$1-\log_{3}{27-x}=5 $$$$=3^5=27-x$$$$=243=27-x$$$$=-x=243-27$$$$=-x=216=-216$$
$$2-\log_{3}{x-1}=3 $$$$=3^3=x-1$$$$=27=x-1$$$$=x=-27-1=-28.$$

anonymous · Answer

theres no -28

jiteshmeghwal9 · Answer

Oops! sorry its x-1=27=>x=27+1=28.

anonymous · Answer

$$Log_3x = 3 + 1 = 4$$

So,

using the above formula:

$$3^4 = x$$

$$x = 3 \times 3 \times 3 \times 3$$

Multiply and get the answer...

anonymous · Answer

This is the solution of Second Question...

jiteshmeghwal9 · Answer

There is the solution of second ques @waterineyes

callisto · Answer

@sara1234 Is it a exam/test?

anonymous · Answer

What are you trying to say???

jiteshmeghwal9 · Answer

I have done the second ques in my reply.

anonymous · Answer

not it's just practice for my test

anonymous · Answer

sample questions why?

anonymous · Answer

There were total 4 question..

You have done anything else but I have done 2 question and just ask you @sara1234 she will clear you..

callisto · Answer

We're not allowed to help other cheat.. But if it's a practice only, we can help.
Have you tried them yet? It's better to tell where you don't understand.