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how do you find co vertices of a graph?
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what
@saisukruth im gonna attach a picture. hold on
vertices = 1st vertices ; (H+-A,K) <- horizontal l (H,K+-A) <- Vertical l 2 vertices ; (H,B+-K) <- Horizontal l (H+-K,B) <- Vertical
To find the vertices, you need points (A), (B) and (K) you find A and B by looking at the denominator, differs between horizontal nad horizontal K is the (Y-K) part, usually = 0
Differs between horizontal and vertival*
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lets say an ellipse; (x-0)^2/16 + (y-k)^2/4 Vertices are ; (0+-4,0) and (0,0+-4) and ((0,2+-0)) and (0,+-2)
oh, a^2 = 5 a= +-Square.r of 5 b^2 = 3 b= +-square.r of 3 then just calc.
@agrin -3,0 and 3,0 ??
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