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Mathematics 7 Online
OpenStudy (anonymous):

how do you find co vertices of a graph?

OpenStudy (anonymous):

what

OpenStudy (anonymous):

@saisukruth im gonna attach a picture. hold on

OpenStudy (anonymous):

vertices = 1st vertices ; (H+-A,K) <- horizontal l (H,K+-A) <- Vertical l 2 vertices ; (H,B+-K) <- Horizontal l (H+-K,B) <- Vertical

OpenStudy (anonymous):

To find the vertices, you need points (A), (B) and (K) you find A and B by looking at the denominator, differs between horizontal nad horizontal K is the (Y-K) part, usually = 0

OpenStudy (anonymous):

Differs between horizontal and vertival*

OpenStudy (anonymous):

OpenStudy (anonymous):

lets say an ellipse; (x-0)^2/16 + (y-k)^2/4 Vertices are ; (0+-4,0) and (0,0+-4) and ((0,2+-0)) and (0,+-2)

OpenStudy (anonymous):

oh, a^2 = 5 a= +-Square.r of 5 b^2 = 3 b= +-square.r of 3 then just calc.

OpenStudy (anonymous):

@agrin -3,0 and 3,0 ??

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