please help here : Prove that the orthocentre of a triangle ABC with A(x1,y1), B(x2,y2) and C(x3,y3) is (x1 tan A + x2 tan B + x3 tan C)/(tan A + tan B + tan C), (y1 tan A + y2 tan B + y3 tan C)/(tan A + tan B + tan C)
@amistre64
@AravindG
that looks hideous
yep it seems to be :P
orthocenter is where the bisectors cross right?
i bet we need to bring right angle triangles oout of the bisectors ,express tan using the angles and get to the result
@mathslover what was ur attempt on this qn?
one minute @AravindG
crossing alts ... not bisectors
i and another user did this ... but we can not proceed further
the setup seems to follow a pattern that only differs by xs and ys
yes a symmetric case
do u have the book arihant trigonometry ?this qn is answered in that book
no @AravindG can u upload the screenshot of that answer please @AravindG
@mathslover : Thats the solution in your attachment.. As you found for point D, Apply the same formula for the point O , such that Point O is on the line A and D.. Do not go for E and any other point.
@amistre64 and @Ganpat can u tell me that how to apply the same formula for the point O ?
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