Differentiate y=e^square root (e^2x) sorry bout the "square root" I'm using iPad please show steps for y prime
Do you mean this: \[ y = \exp(\sqrt{e^{2x}}) \]
I mean y=e^everything inside your brackets
Right. So use the chain rule. For example let u(x) = e^2x, then your function is \[ y = e^{\sqrt{u(x)}} \]
In other words, \[ \frac{dy}{dx} = \frac{dy}{du} \frac{du}{dx} \] Now calculate these two terms on the right.
following?
Yeah thanks sorry trying to figure out if I need to use chain rule twice ?
Yes, you do.
Ahhh yeah I get ya :-) thanks heaps for that james
it might be, y = \[y = e ^\sqrt([2x]) * -2\sqrt{x}\]
* = multiplication..
\[ \frac{dy}{du} = \frac{1}{2\sqrt{u}} e^{\sqrt{u}} \]
where come division comes from ?
because the derivative of \( \sqrt{u} \) is \( 1/(2\sqrt{u}) \).
ahhh. k k, i got confuse.. u seems right..
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