how would I solve 2(x+1)

Question

how would I solve 2(x+1)<-6 (x-3)
I know that 2 multiplied by x is 2 x and 2 multiplied by 1 is 2 and 6 multiplied by x would be 6x and then 6 multiplied by -3 would be -18 so the equation would look like 2x+2<-6x-18 not sure what to do from here
can anyone please help

anonymous · Answer

-6 multiplied by -3 is 18

2x+ 2 <  -6x+18

anonymous · Answer

-2 both sides
2x <  -6x + 16

+6x both sides
8x < 16

divide by 8 both sides~~

anonymous · Answer

where is the 8 coming from

anonymous · Answer

are you taking the 10 and subtracting 2

anonymous · Answer

2x     <  -6x +16
   +6x        +6x

=  8x     <           16

anonymous · Answer

wouldn't you subtract and do the opposite of addition, I am just trying to understand thats all sorry for asking so many questions, then I divide 8 by both sides

anonymous · Answer

"wouldn't you subtract and do the opposite of addition"

i don't get this ._. sry  english isn't my first language

you have to add and subtract a same thing for both sides.


 and then divide by 8 at the end

anonymous · Answer

ok I understand thank you very much for your help!!!!! :)

anonymous · Answer

you re welcome