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Prove that A∩(AUB)=A Do I have have to show that A∩(AUB)⊂A and that A⊂A∩(AUB)????
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if \(A\subset C\) then \(A\cap C=A\)
so I do.
use venn diagram..much easier to prove sets identities
it is sufficient to show that A ⊂(A∩(AUB)) and A∩(AUB) is a subset of A. first we know that AUB will have all the elements of A, so that intersection of A and AUB will also contain all the elements in A, hence A is a subset of A∩(AUB). Now since AUB and intersection of it with A will only have elements of A (because if it contains elements which are not in A, then it will not be intersection of A and AUB lol.) so A∩(AUB) is a subset of A. hence A∩(AUB)=A
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