Which of the following is the equation of the horizontal asymptote of the graph of f(x)=(1/3) x+2^-3.

Question

anonymous · Answer

$$f(x)=\left(\begin{matrix}1 \ 3\end{matrix}\right)x+2$$

anonymous · Answer

-3 at the end.

anonymous · Answer

Yay! @apoorvk (:

anonymous · Answer

C'mon @campbell_st (:

anonymous · Answer

Like it has x+2 a little higher then -3

anonymous · Answer

@knock can help, too. (:

anonymous · Answer

It's minus 3. Not negative.

campbell_st · Answer

well to me its a linear equation if its
$$y = \frac{1}{3} x + 2^{-3}$$

as this is the same as 

$$y = \frac{1}{3} x + \frac{1}{8}$$

anonymous · Answer

No @campbell_st . Yes @apoorvk :D

apoorvk · Answer

@campbell_st she's new, doesn't know LaTeX yet..

anonymous · Answer

LaTeX?

anonymous · Answer

Nevermind lol

apoorvk · Answer

It's a syntax to write out equations the way we do.
Let me see if I can find you a link to understand it, it's easy barely takes 2 minutes.

campbell_st · Answer

this an exponetial curve that hae been moved down 3 units... so the horizontal asymptote is y = -3

anonymous · Answer

I'm confused.. I just want what you were doing before @apoorvk

apoorvk · Answer

okay similar curve, but this time instead of 3 or 4 we have 1/3 raised to 'x', so first get me the graph of $\large (\frac 1 3)^x$, the same way as before.

anonymous · Answer

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