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Mathematics 19 Online
OpenStudy (anonymous):

The rectangular coordinates of a point are given. Plot the point and find two sets of polar coordinates for the point for 0 ≤ theta < 2pi. (-3,-3)

OpenStudy (anonymous):

I got (-3sqrt2,.785) and (-3sqrt2, 3.927)

OpenStudy (anonymous):

@jim_thompson5910

OpenStudy (anonymous):

can you tell me if my answers are right?^^

jimthompson5910 (jim_thompson5910):

The first one has the correct r and theta value, but the second one has an incorrect 'r' value.

OpenStudy (anonymous):

Okay, what would the r value be?..

jimthompson5910 (jim_thompson5910):

So the second one is ( ??? , 3.927)

OpenStudy (anonymous):

wait duh it should be positive

jimthompson5910 (jim_thompson5910):

yes

jimthompson5910 (jim_thompson5910):

you got it

OpenStudy (anonymous):

yay! ok would the rect. coords of (2,0) be (2,0) and (-2,pi)

OpenStudy (anonymous):

@jim_thompson5910

OpenStudy (anonymous):

I mean th polar coords

jimthompson5910 (jim_thompson5910):

yes you are absolutely correct, nice job

jimthompson5910 (jim_thompson5910):

oh and I almost forgot, but in the last one, it's probably best to leave things in terms of pi

OpenStudy (anonymous):

didn't i?

OpenStudy (anonymous):

θ =arctan(-3/-3)=pi/4 or 5pi/4 r=3sqrt(2) 1- (3sqrt(2),pi/4) 2- (3sqrt(2),5pi/4)

jimthompson5910 (jim_thompson5910):

so in instead of 0.785, you would write pi/4

OpenStudy (anonymous):

Oh ok.. what about the other one

jimthompson5910 (jim_thompson5910):

and 3.927 would be 5pi/4

OpenStudy (anonymous):

thx!!

jimthompson5910 (jim_thompson5910):

sure thing

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