Mathematics
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OpenStudy (anonymous):
The rectangular coordinates of a point are given. Plot the point and find two sets of polar coordinates for the point for 0 ≤ theta < 2pi. (-3,-3)
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OpenStudy (anonymous):
I got (-3sqrt2,.785) and (-3sqrt2, 3.927)
OpenStudy (anonymous):
@jim_thompson5910
OpenStudy (anonymous):
can you tell me if my answers are right?^^
jimthompson5910 (jim_thompson5910):
The first one has the correct r and theta value, but the second one has an incorrect 'r' value.
OpenStudy (anonymous):
Okay, what would the r value be?..
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jimthompson5910 (jim_thompson5910):
So the second one is ( ??? , 3.927)
OpenStudy (anonymous):
wait duh it should be positive
jimthompson5910 (jim_thompson5910):
yes
jimthompson5910 (jim_thompson5910):
you got it
OpenStudy (anonymous):
yay! ok would the rect. coords of (2,0) be (2,0) and (-2,pi)
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OpenStudy (anonymous):
@jim_thompson5910
OpenStudy (anonymous):
I mean th polar coords
jimthompson5910 (jim_thompson5910):
yes you are absolutely correct, nice job
jimthompson5910 (jim_thompson5910):
oh and I almost forgot, but in the last one, it's probably best to leave things in terms of pi
OpenStudy (anonymous):
didn't i?
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OpenStudy (anonymous):
θ =arctan(-3/-3)=pi/4 or 5pi/4
r=3sqrt(2)
1- (3sqrt(2),pi/4)
2- (3sqrt(2),5pi/4)
jimthompson5910 (jim_thompson5910):
so in instead of 0.785, you would write pi/4
OpenStudy (anonymous):
Oh ok.. what about the other one
jimthompson5910 (jim_thompson5910):
and 3.927 would be 5pi/4
OpenStudy (anonymous):
thx!!
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jimthompson5910 (jim_thompson5910):
sure thing