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Mathematics 10 Online
OpenStudy (anonymous):

In a listing of one number from each of the ve equivalence classes modulo 5, four of the values are 1211, 218, -100, and -3333. Which equivalence class is missing?

OpenStudy (anonymous):

divide by 5, take the remainder, see which one is missing

OpenStudy (anonymous):

Is it 4 mod (5), the one that is missing?

OpenStudy (anonymous):

first three in your head you get \(1211\equiv 1(5)\) and \(218\equiv 3(5)\)and \(-100\equiv 0(5)\) only need to check -3333

OpenStudy (anonymous):

which is 2(5), leaving 4(5) missing?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

please hear my plea

OpenStudy (anonymous):

Electric Aunt Jamima?

OpenStudy (anonymous):

my all time fave!!!!!

OpenStudy (anonymous):

actually that and dog breath in the year of the plague

OpenStudy (anonymous):

Wish that were an answer to one of these questions.

OpenStudy (anonymous):

Have you seen the movie version? Very strange...

OpenStudy (anonymous):

200 motels?

OpenStudy (anonymous):

No, Uncle Meat had footage which accompanied it.

OpenStudy (anonymous):

wow really? can i youtube it?

OpenStudy (anonymous):

Since I got a Zappa fan to help with one, got any guesses on this one? Determine n between 0 and 19 such that (2311)(3912) n mod 20. Something like 11*12 = 132 = 12 mod(20)?

OpenStudy (anonymous):

I'm sure there are clips, perhaps too obscure.

OpenStudy (anonymous):

i am not sure i get the question

OpenStudy (anonymous):

determine n which will fall in the equivalence class for 2311*3912

OpenStudy (anonymous):

\[(2311)(3912)\equiv n (\text{mod}) 20. \] like that?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

i think since 20 divides 100 you only need the last two digits

OpenStudy (anonymous):

k, so 12

OpenStudy (anonymous):

gonna close this one and move on, thanks for helping

OpenStudy (anonymous):

yes that looks right you computed \(11\times 12\) and then the remainder is 12

OpenStudy (anonymous):

yw

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