In a listing of one number from each of the ve equivalence classes modulo 5, four of the values are 1211, 218, -100, and -3333. Which equivalence class is missing?
divide by 5, take the remainder, see which one is missing
Is it 4 mod (5), the one that is missing?
first three in your head you get \(1211\equiv 1(5)\) and \(218\equiv 3(5)\)and \(-100\equiv 0(5)\) only need to check -3333
which is 2(5), leaving 4(5) missing?
yes
please hear my plea
Electric Aunt Jamima?
my all time fave!!!!!
actually that and dog breath in the year of the plague
Wish that were an answer to one of these questions.
Have you seen the movie version? Very strange...
200 motels?
No, Uncle Meat had footage which accompanied it.
wow really? can i youtube it?
Since I got a Zappa fan to help with one, got any guesses on this one? Determine n between 0 and 19 such that (2311)(3912) n mod 20. Something like 11*12 = 132 = 12 mod(20)?
I'm sure there are clips, perhaps too obscure.
i am not sure i get the question
determine n which will fall in the equivalence class for 2311*3912
\[(2311)(3912)\equiv n (\text{mod}) 20. \] like that?
yes
i think since 20 divides 100 you only need the last two digits
k, so 12
gonna close this one and move on, thanks for helping
yes that looks right you computed \(11\times 12\) and then the remainder is 12
yw
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