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Do you use the quadratic equation for this problem..?
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\[4y ^{2}-20y+25\]
Do you mean quadratic formula?
there's no question here...
BTW, it's NOT an equation though.
or do you mean to just factor the expression?
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Oops.
Do you just use the quadratic formula to solve the equation?
You can, but not necessary for this question, assuming there is '=0' after '4y^2-20y+25'
how? @Callisto
I mean, how is it not necessary?
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You can factor the expression on the left.
(2y-5)(2y-5)?
Yes. That is \[(2y-5)^2=0\]
Take square root on both sides 2y-5 = 0 Now, solve y.
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