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Mathematics 21 Online
OpenStudy (anonymous):

Do you use the quadratic equation for this problem..?

OpenStudy (anonymous):

\[4y ^{2}-20y+25\]

OpenStudy (callisto):

Do you mean quadratic formula?

OpenStudy (anonymous):

there's no question here...

OpenStudy (callisto):

BTW, it's NOT an equation though.

OpenStudy (anonymous):

or do you mean to just factor the expression?

OpenStudy (anonymous):

Oops.

OpenStudy (anonymous):

Do you just use the quadratic formula to solve the equation?

OpenStudy (callisto):

You can, but not necessary for this question, assuming there is '=0' after '4y^2-20y+25'

OpenStudy (anonymous):

how? @Callisto

OpenStudy (anonymous):

I mean, how is it not necessary?

OpenStudy (callisto):

You can factor the expression on the left.

OpenStudy (anonymous):

(2y-5)(2y-5)?

OpenStudy (callisto):

Yes. That is \[(2y-5)^2=0\]

OpenStudy (callisto):

Take square root on both sides 2y-5 = 0 Now, solve y.

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