Factor Completely: r^2 -2r + 36 Steps please.
seems unlikely that this will factor using integers
you are not going to find two integers whose product is 36 and whose sum is -2
So I've noticed, how else can I factor this, is it doable?
\[x=-b \pm \sqrt{b ^{2}-4ac}/2a\]
you can factor it using complex numbers if you like
use the format: \[ax ^{2}+bx+c=0\] and fill in the equation, leave the square roots as square roots if needed
\[2+\sqrt{4-4*36}/2\] will give you one of them, change the + AFTER THE 2 to - for the other
I'm completely lost, I haven't done complex numbers yet.. Let me try that though.
you can probably leave it as\[ 2+\sqrt{-140}/72\] I forgot to multiply 36 by 2 earlier
and 2-... for the other
I don't know how to get a square root for that, if I leave it as that how can I finish factoring the rest of the equation without a determined integer?
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