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Mathematics 7 Online
OpenStudy (anonymous):

Factor Completely: r^2 -2r + 36 Steps please.

OpenStudy (anonymous):

seems unlikely that this will factor using integers

OpenStudy (anonymous):

you are not going to find two integers whose product is 36 and whose sum is -2

OpenStudy (anonymous):

So I've noticed, how else can I factor this, is it doable?

OpenStudy (anonymous):

\[x=-b \pm \sqrt{b ^{2}-4ac}/2a\]

OpenStudy (anonymous):

you can factor it using complex numbers if you like

OpenStudy (anonymous):

use the format: \[ax ^{2}+bx+c=0\] and fill in the equation, leave the square roots as square roots if needed

OpenStudy (anonymous):

\[2+\sqrt{4-4*36}/2\] will give you one of them, change the + AFTER THE 2 to - for the other

OpenStudy (anonymous):

I'm completely lost, I haven't done complex numbers yet.. Let me try that though.

OpenStudy (anonymous):

you can probably leave it as\[ 2+\sqrt{-140}/72\] I forgot to multiply 36 by 2 earlier

OpenStudy (anonymous):

and 2-... for the other

OpenStudy (anonymous):

I don't know how to get a square root for that, if I leave it as that how can I finish factoring the rest of the equation without a determined integer?

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