There are 6 girls and 5 boys in a math class. If the teacher chooses two students at random to answer questions, what is the probability of selecting a boy then a girl?
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OpenStudy (anonymous):
I really need help in this one!
possible answers:
3/11
36/121
6/11
OpenStudy (anonymous):
Total Students in the class: 6 + 5 = 11
Now, firstly, find the probability of selecting a boy:
P(B) = 5/11
Now, One boy is selected, so number of students left behind = 11 - 1 = 10
So, from total of 10 students, Find the probability of choosing a Girl:
P(G) = 6/10
So, Probability of Selecting a boy and then a girl will be:
\[P(A)*P(B) = \frac{5 \times 6}{11 \times 10}\]
\[= \frac{30}{110} = \frac{3}{11}\]
OpenStudy (anonymous):
what will be the probability of selecting a boy and then a girl?
OpenStudy (anonymous):
3/11
OpenStudy (anonymous):
thanks!! you saved me!
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OpenStudy (anonymous):
Welcome dear...
OpenStudy (anonymous):
can I ask you one more small question?
OpenStudy (anonymous):
Sure...
OpenStudy (anonymous):
Why are you asking a question before asking a question..
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OpenStudy (anonymous):
Which of the following simplifies to
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OpenStudy (anonymous):
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OpenStudy (anonymous):
I could not get your question..
Following are what???
OpenStudy (anonymous):
I don't get in neither :(
OpenStudy (anonymous):
I have to simplify that
OpenStudy (anonymous):
the possible answers are
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