Question

Use the discriminant to determine the nature of the roots of 4x2 + 15x + 10 = 0. I'm not understanding this.

Answer 1

For a quadratic equation \(ax^2+bx+c =0 \)
discriminant = b^2 - 4ac
Now, determine what is a, b and c. Plug the values of a, b and c into the above formula and get a value.
if discriminant > 0, you'll have 2 distinct real roots.
if discriminant = 0, you'll have a double real root.
if discriminant < 0, you'll have 2 distinct imaginary roots.

Answer 2

That's what I'm not understanding.. How am I suppose to get A, B, and C?

Answer 3

the coeffecients are you a b and c

Answer 4

in ax^2+bx+c

Answer 5

a -> coefficient of x^2
b -> coefficient of x
c -> constant term

Answer 6

ok idk if mods will get angry at this but callisto is right

b^2 - 4ac

15^2-4*4*10=65

65 is greater than 0 so it has 2 real roots so that is your answer :)

Answer 7

A:no real roots C:one real root
B:two distinct real roots D:three distinct real roots

Answer 8

See, It doesn't have the answer choice though.

Answer 9

it B yes it does :)

Answer 10

Distinct threw me off lol

Answer 11

lol

Answer 12

distinct roots = not repeated / not the same roots

Why don't you try but wait for the answer given by @timo86m ?