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Mathematics 14 Online
OpenStudy (anonymous):

A pool that has 24,375 gallons of water is drained at the end of the summer. The water is drained at a rate of 75 gallons per minute. Let m = minutes. Let g = gallons of water in the pool. a) Write a linear equation that can be used to find the number of gallons of water in the pool after any number of minutes into the draining process.

OpenStudy (anonymous):

Every minute you lose 75 gallons of water, so minutes is always multiplied by the amount lost. To find g, you must take the original amount and subtract it by what it is losing based on minutes. Can you figure this out?

OpenStudy (anonymous):

24375m=g?

OpenStudy (anonymous):

No, what you did was take the original amount and multiply it by m. 24,375 is a constant, just like in the last problem I helped you with. And you're decreasing, so you subtract it by the rate in which it loses water by the amount minutes that have passed, m.

OpenStudy (anonymous):

24375 - 75g = m?

OpenStudy (anonymous):

Almost, remember, you're solving for gallons, g, not minutes, m. Switch the two and you have your answer. It's like saying when you start with 24375 gallons of water, when 1 minute passes, m, 75 gallons have been drained, and g is now 24300, if m was 2, then it would lose 150 gallons making g 24125.

OpenStudy (anonymous):

I meant 24225, sorry.

OpenStudy (anonymous):

so 24375 - 75m = g?

OpenStudy (anonymous):

That's correct!

OpenStudy (anonymous):

thx

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