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Mathematics 11 Online
OpenStudy (anonymous):

The atomic number (Z) of an element whose kα wavelength is λ is 11. The atomic number of an element whose kα wavelength is 4λ is equal to?

OpenStudy (anonymous):

(Z – 1)2λ = constant

OpenStudy (anonymous):

Use this formula.

OpenStudy (anonymous):

(10^2)λ = 4λ(Z – 1)2

OpenStudy (anonymous):

Ok got it.

OpenStudy (anonymous):

its 6.

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