find the three consecutive even integers such that the first times the third is 2 greater than 5 times the second?

Question

terenzreignz · Answer

http://openstudy.com/study#/updates/4feae23ae4b0bbec5cfaa74d

parthkohli · Answer

x, x + 2, x + 4 can be the three even integers.

$ \color{Black}{\Rightarrow x(x + 4) = 2 + 5(x + 2)}$

$ \color{Black}{\Rightarrow x^2 + 4x  =2 + 5x + 10}$

$ \color{Black}{\Rightarrow x^2 + 4x = 12 + 5x }$

$ \color{Black}{\Rightarrow x^2 - x - 12 = 0}$

Solve this quadratic equation.

amistre64 · Answer

2x is an even integer; by default tho

amistre64 · Answer

x, x+2, x+4  are just 3 consecutive even or odd integers i think

amistre64 · Answer

2x, 2x+1, 2x+2  would be 3 consecutive even integers by default

parthkohli · Answer

Uh oh, but it gets you even integers actually

terenzreignz · Answer

@amistre64 
OH NO
2x + 1 is ODD
if 2x is even

O.O

parthkohli · Answer

Well actually solve it and then see the even solution.

amistre64 · Answer

hmmm, math has changed since the 60s it appears :)

answers are a consortium these days lol

terenzreignz · Answer

All I meant is that any even number, if you add one to it, it'll be odd, right? :)

amistre64 · Answer

that is correct, i had half an idea and the other side of my brain forgot to chime in ;)  good catch tho

terenzreignz · Answer

haha, me and my anxiety attacks :D

amistre64 · Answer

this seems to be a popular question, as if it was on some sort of quiz or exam ...

amistre64 · Answer

last time we had a bout of same question-itis ... a teacher had told their students to go ask it on openstudy

anonymous · Answer

amistre64,terenzreignz, parthkholi
thanks :)