Question

if 2 +iroot3 is a root of x^2 + px + q =0 whre p, q are real then (p,q)=?

Answer 1

i'll give a tip,,for any polynomial like this of any degree,,it a+ib is its solution,,
then 110% a-ib will also be its solution..
try now..

Answer 2

i was gonna say conjugate, but that works too :)

Answer 3

:D

Answer 4

did nt understand lol

Answer 5

see if 2+iroot3 is a root, then the other root is 2-iroot3
so sum of roots = p/1=2+iroot3+2-iroot3
p=4

Answer 6

got it thxxx for ur help

Answer 7

Complex roots always occur as conjugate surds. That is, if one of the roots is a+ib, then the other root will be a-ib

So, you can find out the second root using this funda, which would be 2 - i*sqrt3

Answer 8

and q= (2+1root3)(2-iroot3)
try now, nd p will be -4 not 4

Answer 9

Now sum of roots = 4 = -p
and product of roots = 2^2 + 3^2 = q = 13