Question

Find the number of:

\[e^{2+ln3}\]

Answer 1

I know that the \[e^{ln3}\] implies \[3^{1}\] but I don't know what to do with the plus 2.

Answer 2

\[\huge a^{m+n} = a^m . a^n\]

Answer 3

it becomes \(e^2.3^1\)

Answer 4

plugin value of \(e=2.718\)

Answer 5

hope it is clear ?

Answer 6

In my textbook, they left the final answer as 3e^2... So, yes it does help :D. Thanks so much!

Answer 7

ok.. great :)