Write the function f(x)=x^3-2x^2+3x+5 as a polynomial of x-2
Well, it must be third order. So expand it out term by term. Start with (x-2)^3 and then see what you have left i.e., write f(x) = (x-2)^3 + stuff. Once you've figured out what stuff is, you'll be able to find the coefficient A such that f(x) = (x-2)^3 + A(x-2)^2 + other stuff now repeat that step and find the coefficient B such that f(x) = (x-2)^3 + A(x-2)^2 + B(x-2) + constant
thank again @JamesJ
jamesj is of course correct, but if this is for a calc class you can do this: \[f(x)=a(x-2)^3+b(x-2)^2+c(x-2)+d\] \[f(2)=d\] so you can replace \(x\) by 2 in the original expression and find \(d\) immediately then \[f'(x)=3a(x-2)^2+2b(x-2)+c\] and therefore \[f'(2)=c\] replace \(x\) by to in derivative of original expression to get \(c\) lather, rinse, repeat haven't seen @jamesj in a while. where you been?
sat73, how are you? I've been busy! Nice method by the way.
good, and glad you are busy, although we (i at least) missed you here
thanks. I'll drop in now and again, but I have a few things cooking.
great see you around the pool as they say
that sounds good. I'll have Mai Tai please!
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