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OpenStudy (anonymous):
Use the discriminant to determine the nature of the roots of 2x2 + 4x + 3 = 0.
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OpenStudy (anonymous):
for a quadratic equation of the form ax^2+bx+c=0 the discriminant is b^2-4ac
OpenStudy (anonymous):
If \(\large b^2-4ac \) is: positive, then you'll two real solutions; zero, one real solution; negative, then you'll have two complex solutions.
OpenStudy (anonymous):
ya dpalnc is right
OpenStudy (anonymous):
Quadradic: \[\huge x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\] It's the part @nitz and @dpaInc said, with the deductions you'll be using that @dpaInc said. :-)
OpenStudy (anonymous):
And technically if it's zero, it's one double-root solution (the same solution twice). But for most practical purposes you don't have to worry about that.
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OpenStudy (anonymous):
but agent x she has to find the nature of roots not the roots itself
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