Question

What is the point of symmetry for the circle (x + 2)2 + (y – 4)2 = 25?

Answer 1

find intercepts

Answer 2

x=0 => y=3, -3

Answer 3

no y =3,-3 sorry

Answer 4

Equation for a circle, with center at (a,b):
\[(x-a)^2 + (y-b)^2 = radius^2\]

Can you find the center? :-)

Answer 5

The point of symmetry is the center.
\[(x - h)^{2} + (y - k)^{2} = r^{2}\]\[(x + 2)^{2} + (y - 4)^{2} = r^{2}\] Where the center is (-h, -k)