Seth is using the figure shown below to prove Pythagorean Theorem using triangle similarity.
In the given triangle ABC, angle A is 90o and segment AD is perpendicular to segment BC.
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OpenStudy (anonymous):
Which of these could be a step to prove that BC2= AB2 + AC2?
Triangle ADC is similar to triangle BAC by the SAS similarity theorem.
Triangle ADB is similar to triangle CDA by the SAS similarity theorem.
Triangle ADC is similar to triangle BAC by the AA similarity theorem.
Triangle ADB is similar to triangle CDA by the AA similarity theorem.
OpenStudy (anonymous):
OpenStudy (anonymous):
yeah!!!!!!!!!!!!!!
OpenStudy (anonymous):
I spotted you guys
OpenStudy (anonymous):
k
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OpenStudy (anonymous):
This was a problem I had gotten wrong on the test
OpenStudy (anonymous):
Can you give me tips?
OpenStudy (anonymous):
Do you happen to know what type of proof this is?
OpenStudy (anonymous):
ehh
OpenStudy (anonymous):
not really...
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OpenStudy (anonymous):
I think its pythagorean theorem mabye/
OpenStudy (anonymous):
OH! derp...THose 2's are squared...
OpenStudy (anonymous):
k
OpenStudy (anonymous):
tips?
OpenStudy (anonymous):
I believe it's the third one because you would prove them using AA similarity postulate.
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OpenStudy (anonymous):
ehh
OpenStudy (anonymous):
Can you give me steps to reach to this explanation?
OpenStudy (anonymous):
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OpenStudy (anonymous):
Like
OpenStudy (anonymous):
k
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OpenStudy (anonymous):
Do you see how right angles are always congruent?
OpenStudy (anonymous):
I see two right angles...
OpenStudy (anonymous):
Yeah. 90 = 90, so right angles are always congruent to each other right?
OpenStudy (anonymous):
derp. of course!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
OpenStudy (anonymous):
k
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OpenStudy (anonymous):
Get it now?
OpenStudy (anonymous):
so wait
OpenStudy (anonymous):
A=90,A=90=AA?
OpenStudy (anonymous):
THe second congruent angle is that other marked angle. See how it's the same angle in both triangles?