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MIT 18.01 Single Variable Calculus (OCW) 22 Online
OpenStudy (anonymous):

In Problem Set 1, 1F-7b asks you to evaluate dm/dv for m = m0 [1-(v^2/c^2)]^(-1/2). How would you do this? The "0" in "m0" is meant to be a subscript and "c" is a constant. I have been trying to use the product rule but I don't know how to deal with the m0.

OpenStudy (anonymous):

I would say that it is a chain rule problem and that m0 is just another constant. Later, you may consider it to be the initial value in a differential equation. But, in this situation it would still be "just a number" that is treated like a constant coefficient.

OpenStudy (anonymous):

what is problem set 1?

OpenStudy (anonymous):

are you in MIT??????

OpenStudy (anonymous):

No I was trying to do the Assignments provided by the Open Course Ware.

OpenStudy (anonymous):

ya thinking so.....

OpenStudy (stacey):

Since you have constants, the problem would be like taking the derivative of \[7[1-v ^{2}/9]^{-1/2}\] You just have m0 where my 7 is and c62 where my 9 is. Use the chain rule.

OpenStudy (anonymous):

Okay thank you!

OpenStudy (anonymous):

Thanks, that helped me!

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