A basketball was thrown from one end of a court to the other. It had an initial upward velocity of 48 feet per second. How long did it take for the ball to hit the ground? Use the formula h = vt – 16t2.

Question

anonymous · Answer

@Loujoelou Wanna help? :p

anonymous · Answer

Well in my virtual school I would have used the formula h= -16t^2+vt+s. The velocity would be 48 so 
-16t^2+48+0 (I assume that the starting height is 0)
to find t we use 
t=-b/2a So we have
t=-48/2(-16) and we get -48/-32 which is equal to 1.5 Now we put this into the equation
h= -16(1.5)^2+48(1.5)+0
h=-36+72
h=36
That's the only thing I know how to solve for in these equations so hopefully I answered the right thing.

anonymous · Answer

A:3 seconds		C:-3 seconds
B:0.3 seconds		D:-0.3 seconds

anonymous · Answer

Ugh lol thought it was asking for that. Well found the answer on this website- http://answers.yahoo.com/question/index;_ylt=AjKUMTSRV8XtbsqtyLvpTwUjzKIX;_ylv=3?qid=20110530112216AA42Ohx

anonymous · Answer

Cause Idon't know how to solve for the seconds so yeah.

anonymous · Answer

Thanks!

anonymous · Answer

No prob. :)