Two spheres of the same density have a ratio of 4 to 9 in surface area. If the small sphere weighs 10kg, what does the sphere weigh
surface are of sphere is proportional to r^2
\(\huge r1^2 : r2^2 = 4 : 9\)
it says the answer is 33.75 kg but i don't know how to get that
yep.. il walk you through...
okay. Thanks
\(\huge r1 : r2 = 2 : 3 \)
volume of sphere is proportional to r^3 right ?
i guess
yup it is.. we dont need the actual formula here, as we are dealing with ratios. ..
\(\huge r1^3 : r2^3 = 8 : 27\)
If the small sphere weighs 10kg, what does the sphere weigh
what does r1^3 and r2^3 mean?
sphere with \(r1\) radius weighs \(10kg\) we need to find the weight of sphere with \(r2\) radius
they are volume ratios. since the density is same for both spheres, we can use the volume ratio.
volume of sphere = \(\frac{4}{3}\pi r^3\)
is it clear ?
i don't really get that
in question, we are given small sphere's weight. and asking us to compute large sphere's weight right ?
yes
1) weight of a sphere is proportional to volume 2) volume of sphere = 4/3 pi r^3 3) so we can take ratio of r^3 to the weight
since they are of same density, weight is proportional to volume. so we can compare volume ratio to weights, right ?
yea
and volume is proportional to r^3
thats how we got to 8:27
we are given surface area ration : 4 : 9
we started from above, right ?
surface area is proportional to r^2
so, ratio of radius must be : 2 : 3 so, ration of volume must be 2^3 : 3^3
okay
8:27 = 10 : x x = 27*10/8
we are equating volume ratios to weight ratios, because density is same
oh ok
oh I got the answer
below info is needed for this problem : surface area of sphere = \(4\pi r ^2\) volume of sphere = \(\frac{4}{3}\pi r^3\)
since weight follows volume, we took the volume ratio.
hope it becomes clear later :)... maybe !!
thank you for your help
u welcome :)
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